2 functions of devices in dvp-plc – Delta Electronics Programmable Logic Controller DVP-PLC User Manual
Page 126
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2 Functions of Devices in DVP-PLC
DVP-PLC Application Manual
2-98
h) When M1148 = On but M1144 = Off, deceleration will not be enabled and M1148 will be reset. Whenever
M1144 = Off, M1149 will be reset.
i) The number of sections being executed is determined upon the total number of sections. (Max. number of
sections = 10)
j) Acceleration or deceleration is determined upon the start frequency of the next section. That is, if the target
frequency of the current section < the start frequency of the next section, acceleration will take place in the
next section and the target frequency of the next section must > its start frequency. If the target frequency of
the current section > the start frequency of the next section, deceleration will take place in the next section
and the target frequency of the next section must < its start frequency. Correct pulse output cannot be
guaranteed if the user does not follow the rules.
k) When PLC goes from STOP to RUN, M1144 ~ M1149 will be reset to “Off”. When PLC goes from RUN to
STOP, only M1144 will be reset, not M1145 ~ M1149.
l) SA/SX/SC uses parameter table D0 ~ D999 and D2000 ~ D4999. If the used parameter table (including all
the used section parameters) falls off the range, the instruction will not be executed and M1144 will be “Off”.
5. Example
1: Calculate the number of output pulses in every acceleration/deceleration section
Assume you set the start frequency of a section as 200Hz, gap time as 100ms, gap frequency as 100Hz, target
frequency as 500Hz, and target number of pulses as 1,000:
The number of output pulses at start frequency = 200 × 100 / 1,000 = 20
The number of output pulses in the first acceleration gap = 300 × 100 / 1,000 = 30
The number of output pulses in the second acceleration gap = 400 × 100 / 1,000 = 40
The number of output pulses at target frequency = 1,000 – (40 + 30 + 20) = 910
(Please be noted that we suggest this number be bigger than 10.)
Output time for target frequency = 1 / 500 × 910 = 1,820 ms
Total time spent for this section = 1,820 + 3 × 100 = 2,120 ms