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Grass Valley NV9000-SE v.5.0 User Manual

Page 469

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451

NV9000-SE Utilities

User’s Guide

Consider the 4-partition system again. This time, N

AB

= 3, N

BC

= 2, and N

CD

= 4:

Then

(1-hop)
AB = (5 x 2) x 3 = 30
BC = (2 x 5) x 2 = 20
CD = (5 x 2) x 4 = 40

(2-hop)
AC = (AB)(AC) / 2 =

AC

= 30 x 20 / 2 = 600 / 2 = 300

BD = (BC)(CD) / 5 =

BD

= 20 x 40 / 5 = 800 / 5 = 160

(3-hop)
AD = (AB)(BC)(CD) / (d

B

x d

C

) =

AD

= 30 x 20 x 40 / (2 x 5) = 24,000 / 10 = 2400

All Paths
30 + 20 + 40 + 300 + 160 + 2400 = 2950.

(Again, the figure is a maximum, because if you omit certain signal types from certain paths, the
number of paths decreases. The calculations for that situation are not worth the trouble.)

Your tieline configuration will probably be more complex than the examples given here.
Complex configurations can be decomposed into simpler parts and the two formulas (given
under

Simple Tielines

and

Multi-Hop Tielines

on page 447) can then be applied.

A

(HD)

d = 5

C

(HD)

d = 5

B

(SD)

d = 2

D

(SD)

d = 2

3

2

4