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Measurement Computing DBK Part 2 User Manual

Page 37

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DBK Option Cards and Module

899892

DBK43A & DBK43B, pg. 17

Load Cell Example

Load cells come with a mV/V specification; for each volt of excitation at maximum load, the load
cell will output a specific millivolt level. The following equation applies:

Load Cell Output Voltage = (Load

Applied

/Load

Rated

)(Excitation Voltage)(Load Cell Rating)

For this example, lets assume the following:

• We have a 350 ohm, 3000 pound load cell.
• The load cell is rated at 2.05 mV/V
• We are using an excitation of 10 V

By applying these values to the preceding equation we find that the Load Cell Output Voltage
is 20.5 mV.

Load Cell Output Voltage = (3000/3000)(10)(2.05×10

-3

) = 20.5 mV

For 1000 pounds applied load, the Load Cell Output Voltage would be one third of the 20.5 mV
value, i.e., 20.5 mV/3 = 6.833 mV. If we used the entire equation we would see:

Load Cell Output Voltage = (1000/3000)(10)(2.05×10

-3

) = 6.833 mV

Now that we know our sensor’s full-scale voltage, we can calculate the DBK43 module’s voltage
gain. The proper voltage gain allows the full-scale sensor output to correspond to the full-scale input
of the data acquisition device. Full-scale device inputs are:

-5 to +5 V for DaqBook and DaqBoard [ISA type] in bipolar mode
0 to +10 V for DaqBook, DaqBoard [ISA type], and DaqBoard/2000 Series

in unipolar mode

-10 to +10 V for DaqBoard/2000 Series in bipolar mode and for Daq PC-Card
-10 to +10V for LogBooks in bipolar mode
0 to +20 V for LogBooks in unipolar mode

5. Calculate the channel total gain based on the full-scale LogBook or Daq device.

The following equation is used to calculate DBK43 total gain.

Gain

TOTAL

= (Sensor Output Voltage

FULL-SCALE

– Voltage

OFFSET

) / Strain or Load Voltage

OUTPUT

In this example we will use:

• a full-scale sensor output voltage of +5 V [for a DaqBook in bipolar mode].
• a 0.5 V offset (from full-scale) to prevent saturation
• the 10.5 mV Bridge Output Voltage [for 4000 microstrain] from Example 1.

Using the gain equation we get:

Gain

TOTAL

= (5.0 V – 0.5 V) / 10.5 mV = 4.5 V / 0.0105 V = 428.6

6. Determine how the total gain will be distributed between the input amplifier gain, filter gain, and

scaling amplifier gain.
An Example of Total Gain Distribution

: If we round the gain of x428.6 [calculated in the previous

step] down to ×420, then the gain distributions indicated by the following table are possible.

Gain Distribution Options for a Total Gain of x420

Possible Gain Distributions

Gain Stage &
Associated Range

Option A

Option B

Option C

Option D

Input Gain

x100 to x1250

×420 ×100 ×240 ×300

Filter Gain

x1 or x2

Disabled ×2

×1 Disabled

Scaling Gain

x1 to x10

×1 ×2.1

×1.75 ×1.4

Total Gain

×420 ×420 ×420 ×420

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