Electro Cam PL-1746 Series - Manual (Page 96)

5-5 Speed Compensation
Leading/Trailing Edge Speed Compensation (cont’d)
Example for Calculating Leading and Trailing Edge
RPM Glue On Glue Off Difference
1st Line Speed: 200 73
°
156
°
83
°
2nd Line Speed: 680 49
°
144
°
95
°
Note that the length of the pulse is 83
°
at 200 RPM, and 95
°
at 680 RPM. This means
that the leading and trailing edges require different speed compensation values.
Leading Edge: Difference in Position: 73
°
- 49
°
= 24
°
Difference in Speed: 680 RPM - 200 RPM = 480 RPM
Speed Compensation Value: Divide difference in position by difference in speed:
24
°
/480 RPM = 0.05
°
per 1 RPM
Since a shaft at 1 RPM rotates 0.006
°
/msec (see page 4-2), this shaft would require
(0.05/0.006), or 8.3 msec to rotate 0.05
°
. So the correct leading edge speed compen-
sation value to enter is 8.3.
Trailing Edge: Difference in Position: 156
°
- 144
°
= 12
°
Difference in Speed: 680 RPM - 200 RPM = 480 RPM
Speed Compensation Value: Divide difference in position by difference in speed:
12
°
/480 RPM = 0.025
°
/1 RPM
Since a shaft at 1 RPM rotates 0.006
°
/msec, this shaft would require (0.025/0.006), or
4.2 msec to rotate 0.05
°
. So the correct trailing edge speed compensation value to
enter is 4.2.