5 control terminals of customer i/os – NORD Drivesystems BU0750 User Manual
Page 52
NORDAC SK 750E Manual
52
Subject to technical amendments
BU 0750 GB-3311
3.5 Control Terminals of Customer I/Os
Function
Data
Designa-
tion
Customer Units / Special Extension Units
Terminal
Relay
Closing contact
I
max
= 2A
U
max
= 28V DC / 230V AC
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
REL 1.1
X3.1.01 X1.1.01 X2.1.01
X2.1.01
X7.1.01 X6.1.01
-
-
REL 1.2
X3.1.02 X1.1.02 X2.1.02
X2.1.02
X7.1.02 X6.1.02
-
-
REL 2.1
-
X1.1.03 X2.1.03
X2.1.03
-
-
-
-
REL 2.2
-
X1.1.04 X2.1.04
X2.1.04
-
-
-
-
REL 3.1
-
-
-
-
-
-
X10.1.05
-
REL 3.2
-
-
-
-
-
-
X10.1.06
-
REL 4.1
-
-
-
-
-
-
X10.1.07
-
REL 4.2
-
-
-
-
-
-
X10.1.08
-
Reference
voltage source
+10V
I
max
= 10 mA
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
VREF 10V X3.2.11 X1.2.11 X2.2.11
X2.2.11
-
-
-
-
Reference
potential GND
Reference potential for the
inverter connected
to PE via resistor and
capacitor
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
AGND /
0V
X3.2.12 X1.2.12 X2.2.12
X2.2.12
-
-
-
-
GND / 0V
-
X1.4.40 X2.2.40
X2.2.40
X7.2.40 X6.2.40 X10.3.40 X11.1.40
X10.4.40
Analogue input
AIN1 = Differential voltage
input with 0V ... 10V
Ri
40 k
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
AIN1 -
X3.2.13 X1.2.13
-
-
-
-
-
-
AIN1 +
X3.2.14 X1.2.14
-
-
-
-
-
-
AIN1 + AIN 2 = -10V...+10V
Ri
20 k
AIN1 +
-
-
X2.2.14
X2.2.14
-
-
-
-
AIN2 +
-
-
X2.2.16
X2.2.16
-
-
-
-
Analog output
0V ... 10V
I
max
= 5 mA
Resolution = 8 Bit
Accuracy = 0.1 V
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
AOUT1
-
X1.2.17 X2.2.17
X2.2.17
-
-
-
-
AOUT2
-
-
X2.2.18
X2.2.18
-
-
-
-
Digital input
Ri
4 k
High = 7.5V .... 33 V
Low = 0V ... 7.5V
Reaction time = 5ms...15ms
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
DIG IN 1
X3.3.21 X1.3.21 X2.3.21
X2.3.21
X7.2.21 X6.2.21
-
-
DIG IN 2
X3.3.22 X1.3.22 X2.3.22
X2.3.22
X7.2.22
-
-
-
DIG IN 3
X3.3.23 X1.3.23 X2.3.23
X2.3.23
X7.2.23
-
-
-
DIG IN 4
-
X1.3.24 X2.3.24
X2.3.24
X7.2.24
-
-
-
DIG IN 5
-
-
X2.3.25
X2.3.25
X7.2.25
-
-
-
DIG IN 6
-
-
X2.3.26
X2.3.26
-
-
-
-
NOTE:
Input for temperature
sensor under option >BUS<
is only DIG IN 1! and under
>MLT< is only DIG IN 6!
!
Here,
Ri
2 k
High = 2.5V .... 33 V
Low = 0V ... 2.5V
DIG IN 7
-
-
-
-
-
-
X10.2.27
-
DIG IN 8
-
-
-
-
-
-
X10.2.28
-
DIG IN 9
-
-
-
-
-
-
X10.2.29
-
DIG IN 10
-
-
-
-
-
-
X10.2.30
-
DIG IN 11
-
-
-
-
-
-
X10.2.31
-
DIG IN 12
-
-
-
-
-
-
X10.2.32
-
DIG IN 13
-
-
-
-
-
-
-
X11.1.33
Power supply
+15 V
Sum of the currents from all
power supplies to one
inverter:
I
max
= 300 mA
BSC
STD
MLT
MLT 20mA CAN-RJ
PBR
POS
ENC
VO +15 V X3.3.42 X1.3.42 X2.3.42
X2.3.42
X7.2.42 X6.2.42 X10.2.42 X11.1.42
Power supply
+5 V
BSC
STD
MLT
MLT 20mA
CAN
PBR
POS
ENC
VO +5 V
-
X1.4.41 X2.3.41
X2.3.41
-
X6.2.41 X10.4.41 X11.1.41