Cub Cadet ISeries - Manual (Page 128)

ELECTRICAL SYSTEM
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4. Ohm’s Law
Ohm’s Law relates voltage, amperage, and resis-
tance. It states that voltage is the product of resistance
times current.
• It is written as V = I x R.
• In simplest terms, it goes like this:
It takes 1 volt to push 1 amp through a resis-
tance of 1 ohm (1 = 1 x 1).
• This equation can be rearranged using algebra
to solve for any one variable.
• Those who were traumatized by algebra can
represent Ohm’s law as a triangle.
When using the triangle, cover the value to be
found, and the two values left exposed signify
how to obtain that value. See Figure 7.15.
• As an example if the “R” is covered, the “V” is
over the “I” which means “V” divided by ”I” will
solve for the covered letter “R” (V/I = R).
If the “V” is covered, “I” and “R” are exposed on
the same line, meaning that the product of “I”
times “R” will solve for the unknown “V” (I x R =
V).
5. Kirchhoff’s current law
Kirchhoff’s current law deals with nodes. Nodes
are the junction of two or more wires or the junction of a
wire to a component.
Kirchhoff’s current law states that what ever current
goes into a node must come out.
As an example: Three wires are connected with a
wire nut. One wire has 5 amps going into the connec-
tion:
• The sum of the currents coming out of the other
two wires must equal 5 amps. That could be 3
amps in one wire and 2 amps in the other or it
could be 2.5 amps in each wire, but the total
coming out must be the same as the current
going in. See Figure 7.16.
Figure 7.15
V
I R
Figure 7.16
5 Amps
3 Amps
2 Amps
Node