Texas Instruments PLUS TI-89 User Manual
Page 495
478 Appendix A: Functions and Instructions
8992APPA.DOC TI-89 / TI-92 Plus: Appendix A (US English) Susan Gullord Revised: 02/23/01 1:48 PM Printed: 02/23/01 2:21 PM Page 478 of 132
By combining the variations of
part()
, you can
extract all of the sub-expressions in the
simplified result of
expression1
. As shown in
the example to the right, you can store an
argument or operand and then use
part()
to
extract further sub-expressions.
Note:
When using
part()
, do not rely on any
particular order in sums and products.
part(cos(
pù x+3)) ¸
1
part(cos(
pù x+3),0) ¸
"cos"
part(cos(
pù x+3),1)! temp ¸
3+
pøx
temp ¸
pøx+3
part(temp,0) ¸
"+"
part(temp) ¸
2
part(temp,2) ¸
3
part(temp,1)! temp ¸
pøx
part(temp,0) ¸
"ù "
part(temp) ¸
2
part(temp,1) ¸
p
part(temp,2) ¸
x
Expressions such as (x+y+z) and (xì yì z)
are represented internally as (x+y)+z and
(xì y)ì z. This affects the values returned for
the first and second argument. There are
technical reasons why
part(
x+y+z,1
)
returns
y+x instead of x+y.
part(x+y+z) ¸
2
part(x+y+z,2) ¸
z
part(x+y+z,1) ¸
y+x
Similarly, xù yù z is represented internally as
(xù y)ù z. Again, there are technical reasons
why the first argument is returned as yøx
instead of xøy.
part(xù yù z) ¸
2
part(xù yù z,2) ¸
z
part(xù yù z,1) ¸
yøx
When you extract sub-expressions from a
matrix, remember that matrices are stored as
lists of lists, as illustrated in the example to
the right.
part([a,b,c;x,y,z],0) ¸
"{"
part([a,b,c;x,y,z]) ¸
2
part([a,b,c;x,y,z],2)! temp
¸
{x y z}
part(temp,0) ¸
"{"
part(temp) ¸
3
part(temp,3) ¸
z
delVar temp
¸
Done