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C= df = 1 c, 1 + (1– c ), Lower = ( o – Casio CLASSPAD 330 3.04 User Manual

Page 451: T 2, 1 + n, 1upper = ( o, T 2 s, 1lower = ( o, 2 + n, Upper = ( o

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20090601

When the two population standard deviations are equal (pooled)

When the two population standard deviations are not equal (not pooled)

Definition of Terms

C-Level : confidence level (0 C-Level < 1)
List(1) :

list where sample 1 data is located

List(2) :

list where sample 2 data is located

Freq(1) : frequency of sample 1 (1 or list name)
Freq(2) : frequency of sample 2 (1 or list name)
Pooled : On or Off

M

1

:

sample mean of sample 1 data

s

x

1

:

sample standard deviation of sample 1 (s

x

1

0)

n

1

:

size of sample 1 (positive integer)

M

2

:

sample mean of sample 2 data

s

x

2

:

sample standard deviation of sample 2 (s

x

2

0)

n

2

:

size of sample 2 (positive integer)

Calculation Result Output

Lower :

interval lower limit (left edge)

Upper :

interval upper limit (right edge)

df

:

degrees of freedom

M

1

:

sample mean of sample 1 data

M

2

:

sample mean of sample 2 data

s

x

1

:

sample standard deviation of sample 1

s

x

2

:

sample standard deviation of sample 2

s

p

:

pooled sample standard deviation (Displayed only when pooling is
turned on.)

n

1

:

size of sample 1

n

2

:

size of sample 2

Lower = (

o

1

o

2

)– t

2

n

1

+n

2

–2

s

p

2

n

1

1 +

n

2

1

Upper = (

o

1

o

2

)+ t

2

s

p

2

n

1

+n

2

–2

n

1

1 +

n

2

1

Lower = (

o

1

o

2

)– t

2

n

1

+n

2

–2

s

p

2

n

1

1 +

n

2

1

Upper = (

o

1

o

2

)+ t

2

s

p

2

n

1

+n

2

–2

n

1

1 +

n

2

1

Lower = (

o

1

o

2

)– t

df

2

+

n

1

s

x

1

2

n

2

s

x

2

2

Upper = (

o

1

o

2

)+ t

df

2

+

n

1

s

x

1

2

n

2

s

x

2

2

Lower = (

o

1

o

2

)– t

df

2

+

n

1

s

x

1

2

n

2

s

x

2

2

Upper = (

o

1

o

2

)+ t

df

2

+

n

1

s

x

1

2

n

2

s

x

2

2

C

=

df

=

1

C

2

n

1

–1

+

(1–C)

2

n

2

–1

+

n

1

n

1

n

2

s

x

1

2

s

x

1

2

s

x

2

2

C

=

df

=

1

C

2

n

1

–1

+

(1–C)

2

n

2

–1

+

n

1

n

1

n

2

s

x

1

2

s

x

1

2

s

x

2

2

7-10-9

Confidence Intervals