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2 calibration with five measurements, Calibration with five measurements, 1) sin( ) 60 tan( ) cos – Maxim Integrated 71M6541 Demo Board User Manual

Page 38: Tan( ) 60 tan( ) 1, 2) cos( 2, Ae e

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71M6541 Demo Board REV 3.0 User’s Manual

38

Rev 4.0

3a.

[

]

1

)

60

cos(

)

sin(

)

60

sin(

)

cos(

)

60

cos(

60

+

=

S

S

XI

XV

A

A

E

φ

φ

1

)

sin(

)

60

tan(

)

cos(

+

=

S

XI

XV

S

XI

XV

A

A

A

A

φ

φ

Combining 2a and 3a:

4.

)

tan(

)

60

tan(

)

1

(

0

0

60

S

E

E

E

φ

+

+

=

5.

)

60

tan(

)

1

(

)

tan(

0

0

60

+

=

E

E

E

S

φ

6.





+

=

)

60

tan(

)

1

(

tan

0

0

60

1

E

E

E

S

φ

and from 2a:

7.

)

cos(

1

0

S

XV

XI

A

E

A

φ

+

=

Now that we know the A

XV

, A

XI

, and

φ

S

errors, we calculate the new calibration voltage gain coefficient from the

previous ones:

XV

NEW

A

V

CAL

V

CAL

_

_

=

We calculate PHADJ from

φ

S

, the desired phase lag:

[

]

[

]

+

=

)

2

cos(

)

2

1

(

1

)

tan(

)

2

sin(

)

2

1

(

)

2

cos(

)

2

1

(

2

)

2

1

(

1

)

tan(

2

0

9

0

9

0

9

2

9

20

T

f

T

f

T

f

PHADJ

S

S

π

φ

π

π

φ

And we calculate the new calibration current gain coefficient, including compensation for a slight gain increase
in the phase calibration circuit.

2

9

0

9

0

9

20

20

)

2

1

(

)

2

cos(

)

2

1

(

2

1

))

2

cos(

)

2

1

(

2

2

2

(

2

1

1

_

_

+

+

+

=

T

f

T

f

PHADJ

PHADJ

A

I

CAL

I

CAL

XI

NEW

π

π

2.2.2 CALIBRATION WITH FIVE MEASUREMENTS

The five measurement method provides more orthogonality between the gain and phase error derivations. This
method involves measuring E

V

, E

0

, E

180

, E

60

, and E

300

. Again, set all calibration factors to nominal, i.e., CAL_IA

= 16384, CAL_VA = 16384, PHADJA = 0.

First, calculate A

XV

from E

V

:

1.

1

+

=

V

XV

E

A

Calculate A

XI

from E

0

and E

180

:

2.

1

)

cos(

1

)

0

cos(

)

0

cos(

0

=

=

S

XI

XV

S

XI

XV

A

A

IV

A

A

IV

E

φ

φ

3.

1

)

cos(

1

)

180

cos(

)

180

cos(

180

=

=

S

XI

XV

S

XI

XV

A

A

IV

A

A

IV

E

φ

φ

4.

2

)

cos(

2

180

0

=

+

S

XI

XV

A

A

E

E

φ