Texas Instruments TITANIUM TI-89 - Manual (Page 865)

Appendix A: Functions and Instructions 865
right() MATH/List menu
right( list1 [, num ])
⇒ ⇒ ⇒ ⇒ list
Returns the rightmost num elements contained in
list1 .
If you omit num , returns all of list1 .
right({1,3,л 2,4},3) ¸
{3
л
2 4}
right( sourceString [, num ])
⇒ string
Returns the rightmost num characters contained
in character string sourceString .
If you omit num , returns all of sourceString .
right("Hello",2) ¸ "lo"
right( comparison )
⇒ expression
Returns the right side of an equation or
inequality
.
right(x<3) ¸ 3
root() CATALOG/MATH/Number menu
root( expression )
⇒ ⇒ ⇒ ⇒ root
Computes an nth root of x where x can be a real
or complex floating point constant, an integer or
complex rational constant, or a general symbolic
expression.
root(8,3) ¸ 2
root(3,3) ¸ 3 1/3
root(3,0,3) ¸ 1.442249570
rotate() MATH/Base menu
rotate( integer1 [, #ofRotations ]) ⇒ ⇒ ⇒ ⇒ integer
Rotates the bits in a binary integer. You can enter
integer1 in any number base; it is converted
automatically to a signed, 32-bit binary form. If
the magnitude of
integer1 is too large for this
form, a symmetric modulo operation brings it
within the range.
In Bin base mode:
rotate(0b1111010110000110101) ¸
0b10000000000000111101011000011010
rotate(256,1) ¸ 0b1000000000
If #of Rotations is positive, the rotation is to the
left. If #of Rotations is negative, the rotation is to
the right. The default is ë 1 (rotate right one bit).
For example, in a right rotation:
In Hex base mode:
rotate(0h78E) ¸ 0h3C7
rotate(0h78E,ë2) ¸ 0h800001E3
rotate(0h78E,2) ¸ 0h1E38
0b00000000000001111010110000110101
produces:
0b10000000000000111101011000011010
The result is displayed according to the Base
mode.
Important: To enter a binary or hexadecimal
number, always use the 0b or 0h prefix (zero,
not the letter O).
rotate( list1 [, #ofRotations ]) ⇒ ⇒ ⇒ ⇒ list
Returns a copy of list1 rotated right or left by #of
Rotations elements. Does not alter list1 .
If #of Rotations is positive, the rotation is to the
left. If #of Rotations is negative, the rotation is to
the right. The default is ë 1 (rotate right one
element).
In Dec base mode:
rotate({1,2,3,4}) ¸
{4 1 2 3}
rotate({1,2,3,4},ë2) ¸
{3 4 1 2}
rotate({1,2,3,4},1) ¸
{2 3 4 1}
Rightmost bit rotates to leftmost.
Each bit rotates right.