Deltype, Delvar, Desolve() – Texas Instruments TITANIUM TI-89 User Manual
Page 808: 808 appendix a: functions and instructions

808
Appendix A: Functions and Instructions
DelType
DelType
var_type
Deletes all unlocked variables of the type
specified by
var_type
.
Note: Possible values for
var_type
are:
ASM, DATA, EXPR, FUNC, GDB, LIST, MAT, PIC,
PRGM, STR, TEXT, AppVar_type_name, All.
Deltype “LIST” ¸ Done
DelVar
CATALOG
DelVar
var1
[,
var2
] [,
var3
] ...
Deletes the specified variables from memory.
2! a
¸
2
(a+2)^2
¸
16
DelVar a
¸
Done
(a+2)^2
¸
(a
+
2)ñ
deSolve()
MATH/Calculus menu
deSolve(
1stOr2ndOrderOde
,
independentVar
,
dependentVar
)
⇒
⇒
⇒
⇒
a general solution
Returns an equation that explicitly or implicitly
specifies a general solution to the 1st- or 2nd-
order ordinary differential equation (ODE). In the
ODE:
•
Use a prime symbol ( '
, press 2
È
) to
denote the 1st derivative of the dependent
variable with respect to the independent
variable.
•
Use two prime symbols to denote the
corresponding second derivative.
The ' symbol is used for derivatives within
deSolve()
only. In other cases, use
d
( )
.
The general solution of a 1st-order equation
contains an arbitrary constant of the form
@k
,
where
k
is an integer suffix from 1 through 255.
The suffix resets to 1 when you use
ClrHome
or
ƒ
8: Clear Home
. The solution of a 2nd-order
equation contains two such constants.
Note: To type a prime symbol (
'
), press
2
È.
deSolve(y''+2y'+y=x^2,x,y)¸
y=(
@
1шx+
@
2)ш
e
ë
x
+xñì4øx+6
right(ans(1))!temp ¸
(
@
1шx+
@
2)ш
e
ë
x
+xñì4øx+6
d
(temp,x,2)+2ù
d
(temp,x)+tempìx^2
¸
0
DelVar temp ¸ Done
Apply
solve()
to an implicit solution if you want
to try to convert it to one or more equivalent
explicit solutions.
deSolve(y'=(cos(y))^2ùx,x,y) ¸
tan(y)=
xñ
2
+@3
When comparing your results with textbook or
manual solutions, be aware that different
methods introduce arbitrary constants at different
points in the calculation, which may produce
different general solutions.
solve(ans(1),y) ¸
y=tanê
(
2
2 @ 3
2
x
+ i
)
+@n1øp
ans(1)|@3=cì1 and @n1=0 ¸
y=tanê
(
xxxxс +2
+2
+2
+2ш((((ccccì 1111))))
2222
)
deSolve(
1stOrderOde
and
initialCondition
,
independentVar
,
dependentVar
)
⇒
⇒
⇒
⇒
a particular solution
Returns a particular solution that satisfies
1stOrderOde
and
initialCondition
. This is usually
easier than determining a general solution,
substituting initial values, solving for the arbitrary
constant, and then substituting that value into
sin(y)=(yù
e
^(x)+cos(y))y'!ode ¸
sin(y)=(
e
x
ø
y+cos(y))øy'
deSolve(ode and y(0)=0,x,y)!soln
¸
ë
(2øsin(y)+yс)
2
====л((((
e
xxxx
м
1)
1)
1)
1)ш
e
ë
xxxx
ø
sin(y)
sin(y)
sin(y)
sin(y)