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Det-Tronics EQP Fire and Gas Detection/Releasing System SAFETY MANUAL User Manual

Page 16

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5.1

95-8599

14

Figure 3A—X3301 Input in a Typical Low Demand Application

PIRECL

ECLIPSE GAS

DETECTOR

Simplex EQ3xxx

EQP SAFETY

CONTROLLER*

EQ3730EDIO

EQP SAFETY

EDIO**

VALVE

λ

DU = 132

T1 = 1 YEAR

PFDavg = 0.58 x 10

-3

λ

DU = 87.5 + 22.8

T1 = 1 YEAR

PFDavg = (0.38 x 10

-3

+ 0.1 x 10

-3

)

λ

DU = 21.8

T1 = 1 YEAR

PFDavg = 0.1 x 10

-3

λ

DU Valve***

and

Power Supply

λ

DU IS FAILURE RATE PER 10

9

HOURS, T

P

OF 1 YEAR = 8760 HOURS, PFD

avg

IS THE PROBABILITY OF FAILURE ON DEMAND.

PFD

avg

= Σ (

1/2

• T

1

λ

DU

)

*Includes Worst Case Safety Communication

(

λ

DU

= 22.8, PFDavg = 0.1 x 10

-3

)

**Single Output Configuration, Monitored for Opens
***See note in Calculating PFD for Low Demand Applications

Figure 3B—PIRECL Input in a Typical Low Demand Application

EQ3730EDIO

EQP SAFETY

EDIO*

SWITCH

Simplex EQ3xxx

EQP SAFETY

CONTROLLER**

EQ3730EDIO

EQP SAFETY

EDIO***

VALVE

λ

DU = 0.68

T1 = 1 YEAR

PFDavg = 0.003 x 10

-3

λ

DU Switch

λ

DU = 87.5 + 22.8

T1 = 1 YEAR

PFDavg = (0.38 x 10

-3

+ 0.1 x 10

-3

)

λ

DU = 21.8

T1 = 1 YEAR

PFDavg = 0.1 x 10

-3

λ

DU Valve****

and

Power Supply

λ

DU IS FAILURE RATE PER 10

9

HOURS, T

P

OF 1 YEAR = 8760 HOURS, PFD

avg

IS THE PROBABILITY OF FAILURE ON DEMAND.

PFD

avg

= Σ (

1/2

• T

1

λ

DU

)

* Single Input Configuration with Open & Short Monitoring.

λ

DU for Components Common to both Inputs

and Outputs Contained in EDIO and Output

Calculation
** Includes Worst Case Safety Communication
(

λ

DU

= 22.8, PFDavg = 0.1 x 10

-3

)

***Single Output Configuration, Monitored for Opens
****See note in Calculating PFD for Low Demand Applications

Figure 3C—EDIO Input in a Typical Low Demand Application

X3301

IR FLAME

DETECTOR

Simplex EQ3xxx

EQP SAFETY

CONTROLLER*

EQ3730EDIO

EQP SAFETY

EDIO**

VALVE

λ

DU = 133

T1 = 1 YEAR

PFDavg = 0.58 x 10

-3

λ

DU = 87.5 + 22.8

T1 = 1 YEAR

PFDavg = (0.38 x 10

-3

+ 0.1 x 10

-3

)

λ

DU = 21.8

T1 = 1 YEAR

PFDavg = 0.1 x 10

-3

λ

DU Valve***

and

Power Supply

λ

DU IS FAILURE RATE PER 10

9

HOURS, T

P

OF 1 YEAR = 8760 HOURS, PFD

avg

IS THE PROBABILITY OF FAILURE ON DEMAND.

PFD

avg

= Σ (

1/2

• T

1

λ

DU

)

*Includes Worst Case Safety Communication

(

λ

DU

= 22.8, PFDavg = 0.1 x 10

-3

)

**Single Output Configuration, Monitored for Opens
***See note in Calculating PFD for Low Demand Applications