Badger Meter Model IOG - Manual (Page 32)

Example 3
Known values are:
Velocity
= 4 3 ft/sec
Inside Diameter of Pipe = 3 068 in
1)
Find the area of the pipe cross section
2
 
 
 
3.068
2
Area = πr 2
Area = π = π x 2.35 = 7.39 in 2
2)
Find the volume in 1 ft of travel
88.71in 2
7.3 in 2 x 12 in (1 ft) =
ft
3)
What portion of a gallon does 1 ft of travel represent?
= 0.384 gallons
88.71 in 3
231 in 3
So for every foot of fluid travel 0 384 gallons will pass
1)
What is the flow rate in gpm at 4 3 ft/sec?
0 384 gallons × 4 3 FPS × 60 sec (1 min) = 99 1 gpm
Now that the volumetric flow rate is known, all that is needed is an output frequency to determine the K factor
Known values are:
Frequency = 700 Hz (By measurement)
Flow Rate = 99 1 gpm (By calculation)
1) 700 Hz × 60 sec = 42,000 pulses per gallon
2)
= = K factor 42,000 pulses per min
99.1 gpm
423.9 pulses per gallon
ER-500 Flow Monitor
Page 32 August 2013