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Cylinder deflection, Switches, Cushioning performance – Norgren C/146200 LINTRA PLUS User Manual

Page 4

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C/146000, C/146100, C/146200

3/10

N/us 1.6.009.04

Our policy is one of continued research and development. We therefore reserve the right to amend,

without notice, the specifications given in this document.

18 (8)

2204 (1000)

lb. (kg)

inches /s
(m / s)

Ш 16

Ш 20

Ш 25

Ш 32

Ш 40

Ш 50

Ш 63

Ш 80

1763 (800)
1300 (600)

882 (400)

441 (200)

176 (80)

132 (60)

88 (40)

44 (20)

22 (10)

13 (6)

8.8 (4)

4.4 (2)

2.2 (1)

16”
(0.4)

31”
(0.8)

47”
(1.2)

63”
(1.6)

79”
(2.0)

V

Cushioning Performance

The dynamic energy of a LINTRA

®

cylinder is caused by direct or partial external loads

which must be absorbed by pneumatic cushioning.
The cushioning ability depends to a large extent on the pneumatic circuit (e. g. counter
pressure, pre-exhaust). The values given in the diagram were tested with an operation
pressure of 87 psi (6 bar) using a 5/2 control valve. When installed horizontally, depending
upon the speed, dynamic energy can be absorbed by the cylinder. Whenever the values
given in the diagram are exceeded, the transported mass must be cushioned by additional
shock absorbers. These have to be located at the center of gravity of the mass.

inches (mm)

19.7’

(6000)

16.4’

(5000)

13’

(4000)

9.8’

(3000)

6.5’

(2000)

3.2’

(1000)

0

2

0.04” (1)

0.004” (0.1)

0.02” (0.4)

ft.

(mm)

f

0.08” (2)

0.04
(0.9)

Cylinder deflection

72”
(1830)

inches (mm)

f1= 0.04” (1 mm)

2248

(10000)

1124

(5000)

224

(1000)

112

(500)

22.5

(100)

2.25

(10)

0.22

(1)

39”

(1000)

0

6.6’

(2000)

9.8’

(3000)

13’

(4000)

16.4’

(5000)

19.6’

(6000)

Ш80

Ш63

Ш50

Ш40

Ш32

Ш25

Ш20

Ш16

Deflection due to external forces

Support length

Deflection due to cylinder weight

Example:
Cylinder Ø 32 mm, stroke length 11' (3500 mm), external load
45 lbf. (200 N) and a deflection about 0.04 (1 mm).
Maximum distance between supports = 6' (1830 mm) (see diagrams).
Therefore an additional support is required.

Support length

Example:
Cylinder Ø 40 mm. external force 40 lbf (180 N),
distance between supports 10' (3000 mm)
Required: total deflection
1. Deflection due to external force (f1)

see Diagram 1 (1mm /100 N) · 40 lbf (180 N)

2. Deflection due to cylinder weight diagram 2

Total deflection:

Max. permitted deflection (f1 + f2)

A deflection of more than 0.12" (3 mm)
is not permitted.

With cable

With connector (M8x1)

Cable

Cable with

Type

Voltage

Current

Temperature

LED

Features

Connector

Cable

connector

Reed

Solid state

V AC

V DC

max.

°F

length

type

straight

Datasheet

M/50/LSU/*V

10 to 240

10 to 170

180 mA

-4 to +176

8', 33'

PVC 2 x 0.25

N/en 4.3.005

M/50/LSU/5U

10 to 240

10 to 170

180 mA

-4 to +176

16'

PUR 2 x 0.25

N/en 4.3.005

TM/50/RAU/2S –

10 to 240

10 to 170

180 mA

-4 to +302

6.5'

Silicone 2 x 0.25 –

N/en 4.3.005

M/50/RAC/5V

10 to 240

10 to 170

180 mA

-4 to +176

Changeover

16'

PVC 3 x 0.25

N/en 4.3.005

M/50/LSU/CP

10 to 60

10 to 75

180 mA

-4 to +176

Plug M8x1

16'

PVC 3 x 0.25

M/P73001/5

N/en 4.3.005

M/50/EAP/*V

10 to 30

150 mA

-4 to +176

PNP

8', 33'

PVC 3 x 0.25

N/en 4.3.007

M/50/EAP/CP

10 to 30

150 mA

-4 to +176

PNP, plug M8x1

16'

PVC 3 x 0.25

M/P73001/5

N/en 4.3.007

M/50/EAP/CC

10 to 30

150 mA

-4 to +176

PNP, plug M12x1

16'

PVC 3 x 0.25

M/P34614/5

N/en 4.3.007

M/50/EAN/*V

10 to 30

150 mA

-4 to +176

NPN

8', 33'

PVC 3 x 0.25

N/en 4.3.007

M/50/EAN/CP

10 to 30

150 mA

-4 to +176

NPN, plug M8x1

16'

PVC 3 x 0.25

M/P73001/5

N/en 4.3.007

Switches

* Please insert cable length

0.07"(1.8 mm)

+ 0.04"(0.9 mm)

0.2" (2.7 mm)

< 0.04"(1 mm)
39"(1000 mm) Stroke

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