Brother TD-4100N - Manual (Page 61)

When m=0, 1, 2, 3, 4, 6
・ n1 and n2 indicate the number of dot positions.
n1: the remainder from dividing the number of dot positions by 256
n2: the quotient from dividing the number of dot positions by 256
・ First, the data is lined up in one row as follows:
・ One dot of the image data is enlarged as follows according to the value of m.
・ As a result, the image is sized depending on the value of m as follows:
m = 0 48 dots vertically x (n1 + n2 *256) * 6 dots horizontally
m = 1 48 dots vertically x (n1 + n2 *256) * 3 dots horizontally
m = 2 48 dots vertically x (n1 + n2 *256) * 3 dots horizontally
m = 3 48 dots vertically x (n1 + n2 *256) * 2 dots horizontally
m = 4 48 dots vertically x (n1 + n2 *256) * 4 dots horizontally
m = 6 48 dots vertically x (n1 + n2 *256) * 4 dots horizontally
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B7 B6 B5 B4 B3 B2 B1 B0
Relationship between the image data and the dots
１ｂ
ｙｔｅ
１ｂ
ｙｔｅ
１ｂ
ｙｔｅ
１ｂ
ｙｔｅ
…
１ｂ
ｙｔｅ
１ｂ
ｙｔｅ
n1＋n2*256 byte
MSB
LSB
ｍ=０ ｍ=１ ｍ=２ ｍ=３ ｍ=４ ｍ=６