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Table 2 — electrical data – Carrier 50LJ008-014 User Manual

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Table 2 — Electrical Data

UNIT

SOLJ

NOMINAL

VOLTAGE

(60 Hz)

VOLTAGE

RANGE

COMPR

(each)

OFM

IFM

ELECTRIC HEAT*

POWER SUPPLY

DISCONNECT SIZEt

Min

Max

RLA

LRA

FLA

FLA

Nominal

kW**

FLA

MCA

MOCPtt

FLA

LRA

008

(7% Tons)

208/230

(3-phase)

187

254

13.7

82

3.0

5 8

7.8/10 4

12 0/16 0
18 6/24 8

24.0/32 0
31.8/42 2

21 7/ 25 0
33 4/ 38 1
51 7/ 59 7

66 7/ 74 2
88 4/102.0

39 7/ 39 7
39 7/ 39 7
48 9/ 54 9
71 9/ 81 8

90 6/100 0

117 7/134 8

45/ 45

45/ 45
50/ 60

80/ 90||

100/10011
125/15011

42/ 42
42/ 42
45/ 50
66/ 75

83/ 92

108/124

223/223

460

(3-phase)

414

508

6.9

41

1 5

26

13.9

165

27 8
33 0

41.7

167
19.8

33 4
39 7
50 2

196

24 1
28 1
45 0

52 9

65 9

25
25
30
50
60

7011

21

22
26
38
46
58

112

575

(3-phase)

518

632

49

30

1 5

2.6

180

36 0

170

34.0

15 1

24 5

45 7

20

25
50

16

23

42

90

009

(81/2 Tons)

208/230

(3 phase)

187

254

162

84

30

5.8

7 8/10 4

12 0/16 0
18 6/24 8
24 0/32 0

31 8/42.4

21.7/ 25 0
33 4/ 38 1
51 7/ 59 7

66 7/ 74.2
88 4/102.0

45 4/ 45.4
45 4/ 45.4
48 9/ 54 9
71 9/ 81 8

90.6/100 0

117.7/134 8

50/ 50
50/ 50
50/ 60

80/ 9011

100/10011

125/15011

47/ 47
47/ 47
47/ 50
66/ 75

83/ 92

108/124

227/227

460

(3-phase)

414

508

8.0

42

1 5

26

139

16.5
27.8
33.0

41.7

16.7
19.8

33 4
39 7

50 2

22 1
24 1
28 1
45 0

52 9
65 9

25
25
30
50
60

7011

23
23
26
38
46
58

114

575

(3-phase)

518

632

61

33

1 5

26

180

36 0

170

34.0

178

24 5
45 7

20
25

50

19

23
42

96

012

(10 Tons)

208/230

(3-phase)

187

254

192

105

30

58

7 8/10 4

12.0/16 0
24 0/32.0

31 8/42 4
37.5/50 0

21 7/ 25 0
33 4/ 38 1
66 7/ 74 2
88 4/102 0

104 1/120 2

52 1/ 52 1

52.1/ 52 1
52.1/ 54 9
90.6/100 0

117 7/134 8
137.4/127 4

60/ 60
60/ 60
60/ 60

100/100

125/150
150/150

54/ 54
54/ 54
54/ 54

83/ 92

108/124
127/145

269/269

460

(3-phase)

414

508

96

55

1 5

26

165

27 8
33 0

41 7
50.0

198

33 4

39 7
50.2
60 1

25.7
28.1
45 0

52 9
65 9
63 4

30
30
50
60

7011
7011

27
27

41

46
58
69

140

575

(3-phase)

518

632

83

45

1.5

26

18.0
36.0
54 0

170

34 0
51 0

22 8
24 5

45 7
67 0

30
30
50

7011

24
24

42
59

120

014

(121/2 Tons)

208/230

(3-phase)

187

254

22 3

137

30

120

7 8/10.4

12.0/16.0

24 0/32.0
31 8/42 4

37 5/50 0

21 7/ 25 0
33 4/ 38 5
66 7/ 77 0
88 4/102 0

104 2/120 3

65 3/ 65 3
65 3/ 65 3
65 3/ 65 3

98 4/111 2

125 5/142 5
145 3/135 3

80/ soil

80/ 8011

80/ 8011

100/12511
150/15011
150/15011

69/ 69
69/ 69

69/ 69
91/102

115/131

134/152

376/376

460

(3-phase)

414

508

104

69

1 5

54

165

27 8
33 0

41 7
50 0

198

33 4
39 7
50 2
60 1

30 3

31 6
48 5

56 4
69 4
66 9

35
35

50
60

70«
80«

32
32
45

52
64
75

189

575

(3-phase)

518

632

96

55

1 5

54

180

36 0
54 0

170

34 0
51 0

28 5
28 5
49 2
70 5

35
35
50

80«

30
30

45
65

161

FLA

HACR

IFM

LRA

MCA

MOCP

OFM

RLA

LEGEND

Full Load Amp

hull Load Allies
Heating, Air Conditioning and Refrigeration

Indoor (Evaporator) Fan Motor
Locked Rotor Amps
Minimum Circuit Amps
Maximum Overcurrent Protection
Outdoor (Condenser) Fan Motor

Rated Load Amps

‘Heaters are field installed only.

fUsed to determine minimum disconnect size per NEC

“Heater capacity (kW) Is based on heater voltage of 240 v, 480 v or 575 v If power

distribution voltage to unit varies from rated heater voltage, heater kW will vary
accordingly

ttFuse or HACR circuit breaker

([Fusing in single point box provides the required branch circuit protection

NOTES;
1

In compliance with NEC requirements for multimotor and combination load equip­

ment (refer to NEC Articles 430 and 440), the overcurrent protective device for
the unit shall be fuse or HACR breaker The CSA units may be fuse or circuit
breaker

2 Unbalanced 3-Phase Supply Voltage

N e v e r o p e r a t e a m o t o r w h e r e a p h a s e i m b a l a n c e i n s u p p l y v o l t a g e i s g r e a t e r
t h a n 2 %

Use the following formula to determine the % voltage imbalance

% Voltage imbalance

max voltage deviation from average voltage

Example: Supply voltage is 460-3-60

AB = 452

V

BC = 464

V

AC = 455

V

Average Voltage = •

452 + 464

455

1371

3

3

= 457

Determine maximum deviation from average voltage

(AB) 457 - 452 = 5

V

(BC) 464 - 457 = 7

V

(AC) 457 - 455 = 2

V

Maximum deviation is 7 v

Determine % voltage imbalance

7

% Voltage imbalance = 100 x — = 1 53%

^

457

This amount of phase Imbalance is satisfactory as it Is below the maximum al­
lowable 2%

IMPORTANT: If the supply voltage phase imbalance is more than 2%, contact
your local electric utility company immediately

i

= 100 x

average voltage