Cub Cadet RZT-S Series - Manual (Page 86)

RZT-S
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Ohm’s Law
Ohm’s Law relates voltage, amperage, and resistance. It states that voltage is the product of resistance times
current.
• It is written as V = I x R.
• In simplest terms, it goes like this:
It takes 1 volt to push 1 amp through a resis-
tance of 1 ohm (1 = 1 x 1).
• This equation can be rearranged using algebra
to solve for any one variable.
• Those who were traumatized by algebra can
represent Ohm’s law as a triangle. When using
the triangle, cover the value to be found, and
the two values left exposed signify how to
obtain that value. See Figure 7.26.
• As an example if the “R” is covered, the “V” is
over the “I” which means “V” divided by ”I” will
solve for the covered letter “R” (V/I = R).
• If the “V” is covered, “I” and “R” are exposed on the same line, meaning that the product of “I” times “R”
will solve for the unknown “V” (I x R = V).
Kirchhoff’s current law
Kirchhoff’s current law deals with nodes. Nodes are the junction of two or more wires or the junction of a wire to
a component.
Kirchhoff’s current law states that what ever current goes into a node must come out.
As an example: Three wires are connected with a
wire nut. One wire has 5 amps going into the connection:
• The sum of the currents coming out of the other
two wires must equal 5 amps. That could be 3
amps in one wire and 2 amps in the other or it
could be 2.5 amps in each wire, but the total
coming out must be the same as the current
going in. See Figure 7.27.
Figure 7.26
V
I R
Figure 7.27
5 Amps
3 Amps
2 Amps
Node