Step 10) zero-current detection, 2 boost stage design steps, Step 11) determine boost peak current – Cirrus Logic AN379 User Manual
Page 24: An379
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AN379
24
AN379REV2
Step 10) Zero-current Detection
Zero-crossings are detected by AC coupling the drain voltage of FET Q
BUCK
to pin BUCKZCD. Capacitor C2
is sized to monitor the zero crossing of a switching drain node. Typical resonant ringing frequencies in the
CRD1680 are less than 5MHz. Implying that period T
resonant
is greater than 200ns.
Series resistor R5 is added to suppress high frequency ringing on the drain node. The RC circuit connected to
the drain of FET Q
BUCK
is required to have a time delay that is less than resonant period T
resonant
. Capacitor
C2 is 27pF and is sized to reduce power dissipation. Power loss P
C2(loss)
in capacitor C2 is calculated from
where
F
SW
= nominal switching frequency equal to 175kHz
Selecting a larger capacitor will produce more losses. Resistor R5 is selected to hold the RC time constant ,
to less than period T
resonant
. Resistor R5 relationship is defined from Equation 59:
Since the typical stray capacitance on pin BUCKZCD can vary from 1pF to 3pF, resistor R5 is selected to be
6.65k
.
A resistor divider is inserted at the BUCKZCD input to limit input current I
BUCKZCD
to less than or equal to
1.5mA and reduce the zero-crossing switching signal to less than 3V. Resistor R26 is selected to be 2k
to
avoid adding delay to RC time constant
and assist in limiting input current I
BUCKZCD
to be less than 1.5mA.
The voltage across capacitor C2 is calculated at maximum boost output voltage V
BST(max)
and is
approximately ±19V. Resistor R6 is selected to be 35.7k
.
4.2 Boost Stage Design Steps
Step 11) Determine Boost Peak Current
Assuming maximum dim is reached at 120
and allowing for a factor of approximately 2 (k~0.5) for
second stage losses plus boost inductor current ripple.
Using Equation 24 on page 15, solve for target
power P
Target
. See Equation 60:
Using Equation 25 on page 15, calculate boost peak current I
BSTPK(max)
. See Equation 61:
where
V
rect(30
= instantaneous rectified voltage at a conduction angle of 30° and minimum input voltage
P
C2 loss
C2 V
BST
2
F
SW
27pF
28V
2
175kHz
3.7mW
=
=
=
[Eq. 58]
R5
C2
--------
200ns
27pF
-----------------
7.4k
=
=
[Eq. 59]
P
T
et
arg
P
OUT
k
--------------
180
o
dim max
-------------------------
5.15W
0.5
-----------------
180
o
120
o
------------
15.45W
=
=
=
[Eq. 60]
I
BSTPK max
P
T
et
arg
V
rect 30
o
------------------------
15.45W
7.64V
---------------------
2.0A
=
=
=
[Eq. 61]