Regency Hampton HI300 Medium Wood Insert - Manual (Page 8)

8
Hampton HI300 Wood Cast Insert
installation
Clearance Diagram for Installations
Side and Top facing is a maximum of 1.5" thick.
Floor protection must be non-combustible, insula-
tive material with an R value of 1.1 or greater.
* Hearth thickness of 0.5" with k value = 0.84",
r value = 0.6 or greater.
Thermal floor protection not required if unit is
raised 3.5" min. measured from bottom of stove. At
this point the standard ember floor protection will
be required. It will need to be a non-combustible
material that covers 16" (406 mm) to the front
of the unit (in Canada 18" (450 mm) and 8" (200
mm) to the sides.
All floor protection must be non-combustible (i.e.,
metals, brick, stone, mineral fiber boards, etc.) Any
organic materials (i.e. plastics, wood paper prod-
ucts, etc.) are combustible and must not be used.
The floor protection specified includes some form
of thermal designation such as R-value (thermal
resistance) or k-factor (thermal conductivity).
** a non-combustible mantel may be installed
at a lower height if the framing is made of
metal studs covered with a non-combustible
board.
** Max. mantle depth is 10" (254mm)
MasonrY and factorY Built fireplace clearances
The minimum required clearances to combustible materials when installed into a masonry or factory built fireplace are listed below.
note: Clearances are the same with standard or oversize cast faceplate.
Minimum Hearth extension for the front (e) and sides
(G) are measured from the fuel door opening.
HoW to deterMine if alternate
floor protection Materials are acceptaBle
The specified floor protector should be 3/8"
(18mm) thick material with a K - factor of
0.84.
The proposed alternative is 4" (100mm) brick
with a C-factor of 1.25 over 1/8" (3mm) mineral
board with a K-factor of 0.29.
step (a):
Use formula above to convert specification
to R-value.
R = 1/k x T = 1/0.84 x .75 = 0.893.
step (b):
Calculate R of proposed system.
4" brick of C = 1.25, therefore
Rbrick = 1/C = 1/1.25 = 0.80
1/8" mineral board of k = 0.29, therefore
Rmin.bd. = 1/0.29 x 0.125 = 0.431
Total R = Rbrick + Rmineral board =
0.8 + 0.431 = 1.231.
step (c):
Compare proposed system R of 1.231 to
specified R of 0.893. Since proposed system
R is greater than required, the system is
acceptable.
definitions
thermal conductance:
C = Btu = W
(hr)(ft 2 )( o F) (m 2) )(K)
thermal conductivity:
k = (Btu)(inch) = W = Btu
(hr)(ft 3 )( o F) (m)(K) (hr)(ft)( o F)
thermal resistance:
R = (ft 2 )(hr)( o F) = (m 2 )(K)
Btu W
A
B C
D
G
F
E
Unit
adjacent
side Wall
(to side of unit)
a
mantle**
(to top)
b
top
facing
(to top)
c
side
facing
(to side of Unit)
D
minimum
Hearth
extension*
e
minimum
Hearth
thickness*
f
minimum
Hearth
thickness*
G
Wood cast
insert
(Hi300 )
11"/280mm 20"/508mm 12"/305mm Reg. F/P
14"/356mm O/S F/P
8"/200mm Reg. F/P
11"/279mm O/S F/P 18"/455mm
0.5"/13mm 8"/200mm