Remko pww, Calculation example and explanation – REMKO PWW Series User Manual
Page 30
30
REMKO PWW
Calculation example and explanation
We reserve the right to make changes to dimensions and design in the interest of technical advances.
1. Determination of the air volume V
L
(m
3
/h)
The following data is provided
in the ratings tables (page 30).
Air capacity
V
= 5400/4300 m
3
/h
Heat output
Q
= 50.1/42.7 kW
Air outlet temp.
t
L2
= 43/45°C
this results in an air heating of
∆t = 28/30 K
The individual pressure difference values D
(see page 31) are added:
Filter box FK
7
Air outlet nozzle AD
9
Total difference =
16
Solution from the diagram:
V
L
= 3400/2400 m
3
/h
The heat outputs shown in the ratingtables are subject to variation as a result of:
Reduced air volumes with additionally mounted accessories such as
(mixed-air box, filter box, air outlet nozzle, etc.). Observe pressure difference values!
Determination of heat output and air volume when using accessories:
Actual:
Unit type PWW 80-3
with filter box FK
with ceiling air outlet nozzle AD
Heating medium PWW 90/70
Air inlet temperature t
L1
= 15°C
Required:
Air volume
V
L
(m
3
/h)
Heat output
Q
L
(kw)
Air outlet temperature t
L2
(°C)
Heating medium resistance
∆p
W
(kPa)