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Using the board, Power supply schemes – Avago Technologies ACPL-P345-000E User Manual

Page 6

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6

Using the Board

It is easy to prepare the evaluation board for use. You just need to solder cables for DC supplies, have proper cables for

HVDC+/HVDC- high voltage bus, and load connections. The evaluation board has a default connection as shown in

Table 1 when it is shipped to the customer. We offer several power supply schemes from which you can choose.

Power Supply Schemes

The evaluation board is built with DC supply flexibility in mind; choose a power supply scheme from the seven available.

Table 1 shows all the possible power supply schemes that work for the evaluation board. A description of each scheme

is given; you are encouraged to explore each scheme and decide which one works best for your needs:
1. Scheme 1 is the simplest and possibly the cheapest scheme. A +5 V isolated DC supply is supplied externally to

power the low voltage V

cc1

circuit. Another external supply (+12 V~20 V for V

cc2a

) is needed for the gate driver driving

the power MOSFET at the bottom inverter arm. V

cc2b

supply is obtained from V

cc2a

by bootstrapping. For this to

work, the bootstrap components D3b and R6 must be connected, all S2 jumpers must be shorted so that no negative

supply of V

ee

is allowed, and the Signal Input 2 is at 180

° out of phase to Signal Input 1. All S2 jumpers are shorted to

connect V

ee

to V

e

so that there are no negative supplies. S3 jumpers are shorted by default but this has no effect on

actual operation of the board. Contact Avago Technologies if bootstrapping operation works are required.

2. Scheme 2 is similar to Scheme 1: it has V

cc1

and V

cc2a

supplies. However, as the power MOSFET used gets bigger,

so does the driving power. Because a bootstrapped power supply can only handle a lower driving power, it is not

suitable for use when Qg of power MOSFET rises above 200 nanocoulombs (nC). A third external supply (+12 V~ 20

V for V

cc2b

) will be needed.

3. Scheme 3 is similar to Scheme 2 in that it uses three external supplies at V

cc1

, V

cc2a

and V

cc2b

. Scheme 3, however, has

the advantage of getting negative supplies for V

ee

(or V

eea

and V

eeb

) by introducing a 12 V Zener diode at D4 and R7

of around 1 k

Ω to provide proper biasing current at D4. For this scheme to work, both the S2 and S3 jumpers must be

open while the external supplies (+15 V ~ 24 V) on the high voltage driver side are to be connected across V

cc2

and V

ee

pins only, not the V

e

pin. As the external supply changes from +15 V to +24 V, V

cc2

will stay at +12V, but V

ee

changes

from -3 V to -12 V, all w.r.t. virtual ground at V

e

.

4. Scheme 4 is another simple scheme; an alternative to Scheme 1. Here, only one external supply for V

cc1

is needed.

V

cc2a

is obtained by a lower power DC/DC converter at IC2a, with V

cc1

as V

in

and +12 V output at V

cc2a

w.r.t. V

ea

. V

cc2b

supply is obtained from V

cc2a

by bootstrapping. For this to work, the bootstrap components D3b and R6 must be

connected, all S2 jumpers must be shorted so that no negative supply of V

ee

is allowed, and the Signal Input 2 should

be 180

° out of phase to Signal input 1. S2 is shorted to connect V

ee

to V

e

so that there is no negative supply. S3

jumpers are shorted by default but this has no effect on actual operation of the board.

5. Scheme 5 is similar to Scheme 4: it has V

cc1

and a DC/DC converter for V

cc2a

. However, as the power MOSFET used

gets bigger, so does the driving power. Because a bootstrapped power supply can only handle a lower driving power,

it is not suitable for use when Qg of power MOSFET rises above 200 nanocoulombs (nC). A second DC/DC converter at

IC2b with V

cc1

as V

in

and +12 V output at V

cc2b

w.r.t .V

eb

. All S2 jumpers are shorted to connect V

ee

to V

e

so that there

are no negative supplies. S3 jumpers are shorted by default but this has no effect on actual operation of the board.

6. Scheme 6 is similar to Scheme 5 with the use of V

cc1

and two DC/DC converters. Each DC/DC converter, however, has

dual outputs set at ±12 V to allow for the availability of negative V

ee

(at V

eea

and V

eeb

). Therefore, all S2 jumpers must

be open, while all S3 jumpers must be shorted.

7. Use Scheme 7 if dual-output ±12 V DC/DC converters are not available or dual-output ±9 V DC/DC converters are

preferred. 12 V V

cc2

can still be obtained using ±9 V DC/DC converters by introducing a 12V Zener diode at D4 and R7

of around 1k

Ω to provide proper biasing current at D4. For this scheme to work, both the S2 and S3 jumpers must be

open. As the total voltage across V

cc2

w.r.t. V

ee

stays at 18V (=9V+9V), V

cc2

of 12 V will be obtained through the 12 V

D4 Zener diode, and -6V at V

ee

, all w.r.t. virtual ground at V

e

.

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