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Specifications – Empire Comfort Systems VFHS-20/10T-4 User Manual

Page 6

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Page 6

16717-2-0605

Model

VFHS-20R

VFHS-20/10T

Input Maximum

20,000

20,000/10,000

Minimum

14,000

7,000/7,000

Minimum Firebox Opening
Height

26 3/4"

26 3/4"

Depth

11 1/4"

11 1/4"

Front Width

23 1/4"

23 1/4"

Rear Width

17 1/4"

17 1/4"

Gas Inlet

3/8"

3/8"

SPECIFICATIONS

Accessories

VFS-BK

Automatic Blower

EHL-24-1

Brick Liner

VPP1A-22

Aged Brick Liner

Accessories For VFHS-20R Only

FRBC-1

Battery Operated Remote Control

FRBTC-1

Battery Operated Remote Control

w/Thermostat

FREC-1

Electric Remote Control

FWS-1

Wall Switch

GWSG-T

Wall Thermostat, Millivolt

TMV

Wall Thermostat, Millivolt - Reed Switch

TRW

Wireless Remote Wall Thermostat

Water vapor is a by-product of gas combustion. An unvented room

heater produces approximately one (1) ounce (30ml) of water for

every 1,000 BTU's (.3KW's) of gas input per hour. .
Unvented room heaters are recommended as supplemental heat (a

room) rather than a primary heat source (an entire house). In most

supplemental heat applications, the water vapor does not create a

problem. In most applications, the water vapor enhances the low

humidity atmosphere experienced during cold weather.

The following steps will help insure that water vapor does not

become a problem.

1. Be sure the heater is sized properly for the application, including

ample combustion air and circulation air.

2. If high humidity is experienced, a dehumidifier may be used

to help lower the water vapor content of the air.

3. Do not use an unvented room heater as the primary heat

source.

This heater shall not be installed in a confined space or unusually

tight construction unless provisions are provided for adequate

combustion and ventilation air.
The National Fuel Gas Code defines a confined space as a space

whose volume is less than 50 cubic feet per 1,000 Btu per hour

(4.8m

3

per kw) of the aggregate input rating of all appliances

installed in that space and an unconfined space as a space whose

volume is not less than 50 cubic feet per 1,000 Btu per hour (4.8

m

3

per kw) of the aggregate input rating of all appliances installed

in that space. Rooms communicating directly with the space in

which the appliances are installed, through openings not furnished

with doors, are considered a part of the unconfined space.
Unusually Tight Construction

The air that leaks around doors and windows may provide enough

fresh air for combustion and ventilation. However, in buildings

of unusually tight construction, you must provide additional fresh

air.

Unusually tight construction is defined as construction

where:

a. Walls and ceilings exposed to the outside atmosphere have

a continuous water vapor retarder with a rating of one perm

or less with openings gasketed or sealed, and

b. Weatherstripping has been added on openable windows and

doors, and

c. Caulking or sealants are applied to areas such as joints

around window and door frames, between sole plates and

floors, between wall-ceiling joints, between wall panels,

at penetrations for plumbing, electrical, and gas lines, and

at other openings.

If your home meets all of the three criteria above, you must

provide additional fresh air. See “Ventilation Air From

Outdoors,” page 7.

Determining if You Have a Confined or Unconfined Space

Use this worksheet to determine if you have a confined or unconfined

space.

Space: Includes the room in which you will install heater plus

any adjoining rooms with doorless passageways or ventilation

grills between the rooms.
1. Determine the volume of the space (length x width x height).

Length x Width x Height =

cu. ft. (volume

of space)

Example: Space size 16 ft. (length) x 10 ft. (width) x 8 ft. (ceiling

height) = 1,280 cu. ft. (volume of space)

If additional ventilation to adjoining room is supplied with

grills or openings, add the volume of these rooms to the total

volume of the space.

2. Divide the space volume by 50 cubic feet to determine the

maximum BTU/Hr the space can support.

(volume of space) ÷ 50 cu. ft. = (maximum

BTU/Hr the space can support)

Example: 1,280 cu. ft. (volume of space) ÷ 50 cu. ft. = 25.6

or 25,600 (maximum BTU/Hr the space can

support)

WATER VAPOR: A BY-PRODUCT OF UNVENTED ROOM HEATERS

PROVISIONS FOR ADEQUATE COMBUSTION & VENTILATION AIR

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