Liquid Controls IT275N - Manual (Page 8)

Sponsler, Inc. IT275N Remote Totalizer & Rate Indicator pg. 8 DOC#: MN-275N-A
Example 3:
Assume a turbine has a K-Factor of 79.58 pulses per SCF and the customer product
demand is 520,000 SCF a day
C.F. = 1/79.58 = .0125659 = .12566
÷ 10 Note: Both conditions are met
Without the ‘0-1’ function:
S3 #2 ‘ON’ (
↓ Position) for ÷ 10 (moves decimal right 1 place)
S5@1, S6@2, S7@5, S8@7 (.1257 rounding 4
th
digit)
S4 in ‘0’ Position (0.1257)
A usage of 520,000 SCF = 41,381,600 total pulses (520,000 x 79.58) and using the C.F.
of S4-S8 the displayed quantity is 520,166 SCF ( 41,381,600 x .1256 )
10
rather than 520,000 for a difference of 166 SCF.
With the ‘0-1’ function: Set S3 #3 ‘ON’ (
↓ Position) for ÷ 100 (moves decimal right 2 places)
Set S5@2, S6@5, S7@6, S8@6 (.2566)
Set S4 in ‘1’ Position (1.2566)
As stated above the 24 hr usage is 520,000 SCF. The displayed quantity is now 520,001
SCF
( 41,381,600 x 1.2567 ) for a difference of 1 SCF
100
Change of Calibration Engineering Units
Assume that liters rather than gallons are the desired engineering units.
Example 4:
K-Factor = 250 pulses per gallon
Liters = 3.785 per gallon
C.F. = Units per Gallon
Pulses per Gallon
C.F. = 3.785/250 = .01514 for display of liters
On the IT275I PCB:
Set S3 #2 ‘ON’ (
↓ Position) moves decimal point right 1 place
On the IT275F P.C.B:
Set S5@1, S6@5, S7@1, S8@4 (.1514)
Set S4 in ‘0’ Position (0.1514)
Note: The ‘0-1’ function was not incorporated because only 1 of the 2 conditions was met
C.F.’s 1
st
digit right of decimal is 1
Example 5:
The Engineering Unit is pounds in 10
th
s CO
2
K-Factor = 250 pulses per gallon
Pounds of CO
2
= 8.470 per gallon
In order to establish 10
th
s, increase lbs./gal. by a factor of 10
Formula 3