Bimba PCS - Manual (Page 21)

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17. APPLICATION EXAMPLES
PFC Example
Suppose we have just finished the installation procedure for a Bimba PFC
Cylinder with 10 inches of stroke, and are using a 0-10 VDC input command
signal. There is a retracted hard stop at 1.5 inches of cylinder stroke and an
extended hard stop at the 9.0 inches of cylinder stroke. Therefore:
• After adjusting the Span setting, 10 volts is equivalent to 9.0 inches of
cylinder rod extension.
• After adjusting the Zero setting, 1.5 inches of cylinder rod extension will
equal 0 volts.
Therefore, 0 to 10 volts covers the 7.5 inch (9.0" - 1.5") range of motion
Using the Formula shown in the Glossary Yields:
To command the PFC to go to a position that is 2.0 inches extended from the
retracted hard stop, the command signal would be calculated as follows:
CS = 2 x 10/7.5 + 0 = 2.667 VDC Command Input Signal
If a 4-20 mA signal is used, the command input signal would be calculated as
follows:
CS = 2 x 16/7.5 + 4 = 8.267 mA Command Input Signal
PTF Example
Suppose we have just finished the installation procedure for a Bimba PTF Rotary
actuator with 200 degrees of rotation, and a 0-10 VDC command input signal.
There is a zero rotational hard stop at 10 degrees of rotation and a full scale
rotational hard stop at 190 degrees of rotation. Therefore:
• After adjusting the Span setting, 10 volts is equivalent to 190 degrees of
rotation
• After adjusting the Zero setting, 10 degrees of rotation will equal 0 volts.
.
Therefore, 0 to 10 volts covers 180 degrees (190 - 10) of motion.
To command the actuator shaft to rotate to a position that is 45 degrees rotated
from the zero hard stop, the command voltage would be calculated as follows:
CS = 45 x 10/180 + 0 = 2.50 VDC Input Command Signal
If a 4-20 mA input command signal is used, the command input would be
calculated as follows:
CS = 45 x 16/180 + 4 = 8 mA Command Input Signal