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TeeJet LH 1000 User Manual

Page 8

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E

NCODING THE

LH 1000

LH 1000 O

PERATORS

& F

ITTING MANUAL

8

LH A

GRO

Example:
In the following example we assume that we use a tractor with a wheel
circumference of 500 cm and 2 magnets fitted to the wheel:
Measurement shows that the effective wheel circumference = 500.6 cm.
There are 2 magnets fitted so the effective wheel circumference needs to be
divided with 2.
500.6 : 2 = 250.3 cm
Encode this as 250

WHEEL CIRCUMFERENCE WITH A MAGNET FITTED TO CARDAN SHAFT

A magnet can be fitted to the cardinal shaft if, for some reason, it is not possible to
fit any magnets onto a wheel. To determine the value to be entered as the "wheel
circumference" use the following procedure:

Step Key Procedure

1

Enter a working width of 9999 as described on page 7.

2

Press the area total key.

3

Drive slowly forward until 1 appears on the display STOP
IMMEDIATELY.

4

Make a mark on the field and on the tire.

5

Drive until the display changes from 10 to 11 STOP
IMMEDIATELY.

6

Make a mark on the field again.

7

Measure the distance between the 2 marks on the field. Divide this
distance with 10.

8

Press the wheel circumference key and an >0< appears on the left
of the display indicating that "wheel circumference" has been
selected.

9

Encode the value determined in steps 1 to 7 using the numerical
keys.

10

The encoded value is stored automatically until another wheel
circumference is encoded; press any other key to leave this
encodement.


Remember to encode the correct working width for the implement again!