Lm358, Low power dual operational amplifiers, New prod uc t typical single-supply circuit – Diodes LM358 User Manual
Page 5: Continued) (v, Comparator with hysteresis, Ac coupled inverting amplifier, Dc coupled low-pass rc active filter

LM358
LOW POWER DUAL OPERATIONAL AMPLIFIERS
LM358
Document number: DS35167 Rev. 2 - 2
5 of 14
February 2011
© Diodes Incorporated
NEW PROD
UC
T
Typical Single-Supply Circuit
(Continued) (V
+
=5.0V
DC
)
+
-
V
O
R2
10M
+V
IN
Comparator with Hysteresis
+V
REF
R1
10K
+
-
V
O
R2
10M
+V
IN
Comparator with Hysteresis
+V
REF
R1
10K
AC Coupled Inverting Amplifier
+
-
R1
10K
V
IN
+
C
IN
R
f
10K
R2
100K
R3
100K
C1
10?F
+
R
B
6.2K
R
L
10K
C
O
V
O
0
3 Vpp
AV= (As shown, A
V
=10)
R
f
R1
V
+
AC Coupled Inverting Amplifier
+
-
R1
10K
V
IN
+
C
IN
R
f
10K
R2
100K
R3
100K
C1
10?F
+
R
B
6.2K
R
L
10K
C
O
V
O
0
3 Vpp
AV= (As shown, A
V
=10)
R
f
R1
V
+
+
-
V
O
R4
1M
+V
CM
Ground Referencing a Differential
Input Signal
V
R
R1
1M
R2
1M
R3
1M
R
+
-
V
O
=V
R
+
-
V
O
R4
1M
+V
CM
Ground Referencing a Differential
Input Signal
V
R
R1
1M
R2
1M
R3
1M
R
+
-
V
O
=V
R
AC Coupled Non-Inverting Amplifier
+
-
V
IN
+
C
IN
R1
100K
C1
0.1?F
+
R
B
6.2K
R
L
10K
C
O
V
O
0
3 Vpp
R 2
1M
R3
1M
C2
10?F
R4
100K
R5
100K
V
+
A
V
=1+
R2
R1
A
V
=11(As Shown)
AC Coupled Non-Inverting Amplifier
+
-
V
IN
+
C
IN
R1
100K
C1
0.1?F
+
R
B
6.2K
R
L
10K
C
O
V
O
0
3 Vpp
R 2
1M
R3
1M
C2
10?F
R4
100K
R5
100K
V
+
A
V
=1+
R2
R1
A
V
=11(As Shown)
+
-
V
O
R4
100K
V
IN
DC Coupled Low-Pass RC Active Filter
R1
16K
R2
16K
C1
0.01?F
C2
0.01?F
R3
100K
V
O
f
O
0
f
O
= 1KHz
Q = 1
A
V
=2
+
-
V
O
R4
100K
V
IN
DC Coupled Low-Pass RC Active Filter
R1
16K
R2
16K
C1
0.01?F
C2
0.01?F
R3
100K
V
O
f
O
0
f
O
= 1KHz
Q = 1
A
V
=2
High Input Z, DC Differential Amplifier
+
-
V
O
+
-
R3
100K
R 4
100K
R2
100K
R1
100K
+V
1
+V
2
R1
R2
R4
R3
For =
(CMRR depends on this
resistor ratio match)
V
O
= (1+ )(V
2
-V
1
)
R4
R3
As Shown: V
O
= 2(V
2
-V
1
)
High Input Z, DC Differential Amplifier
+
-
V
O
+
-
R3
100K
R 4
100K
R2
100K
R1
100K
+V
1
+V
2
R1
R2
R4
R3
For =
(CMRR depends on this
resistor ratio match)
V
O
= (1+ )(V
2
-V
1
)
R4
R3
As Shown: V
O
= 2(V
2
-V
1
)