Casio ALGEBRA FX2.0 series - Manual (Page 20)

○ ○ ○ ○ ○
Example 2 To graph the solution of the system of first order differential equations
below.
(
y
1
)
n = (2 – ( y
2
)) ( y
1
)
( y
2
) n = (2 ( y
1
) – 3) ( y
2
)
x
0
= 0, ( y
1
)
0
= 1, ( y
2
)
0
= 1/4, 0 < < < < < x < < < < < 10, h = 0.1.
Use the following V-Window settings.
Xmin = –1, Xmax = 11, Xscale = 1
Ymin = –1, Ymax = 8, Yscale = 1
Procedure
1 m DIFF EQ
2 4(SYS)
3 2(2)
4 (c- 3( yn )c)*3( yn )
b w
(c* 3( yn )b-d
)* 3( yn )cw
5 a w
b w
b/e w
6 5(SET)b(Param)
7 a w
ba w
8 a.b w* 1 i
9 5(SET)c(Output)4(INIT)
cc1(SEL)
(Select (
y
1
) and ( y
2
) to graph.)
ff2(LIST)bw(Select LIST1
to store the values for
x in LIST1)
c2(LIST)cw (Select LIST2 to
store the values for (
y
1
) in LIST2)
c2(LIST)dw (Select LIST3 to
store the values for (
y
2
) in LIST3)* 2
i
0 !K(V-Window)
-bwbbwbwc
-bwiwbwi
! 6(CALC)
5-3
System of First Order Differential Equations
* 1 * 2
Result Screen
( y
2
)
( y
1
)