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Floor protector material calculations – Vogelzang VG650ELG (new as of 2013) User Manual

Page 20

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Page 20

| VG650ELG MOUNTAINEER™

www

.vogelzang.com

VGZ-025 | 20120424.1

FLOOR PROTECTOR MATERIAL CALCULATIONS

This stove has been tested for and must be installed on a floor protector with the proper Thermal

Resistance or R-value as stated in the installation instructions on page 6, “Locating Stove” step 1, of
this manual. If the floor protector materials listed in the instructions are not available, materials with
an equivalent R-value may be substituted.

Alternate materials may be rated with C-factor (Thermal Conductance) or k-factor (Thermal

Conductivity) ratings which must be converted to R-value to determine if the alternate material meets
the tested requirements. The following instructions provide the proper information and formulas for
conversion to R-value.

To determine if alternate materials are acceptable follow this sequence.

1. Convert material specifications to R-value:

a. R-value given — no conversion necessary
b. k-factor is given with a required thickness (T) in inches:

R = 1/k x T

c. C-factor is given: R = 1/C

2. Determine the R-value of proposed alternate floor protector:

a. Use formulas in step 1 above to calculate R-value of proposed material(s).

b. For multiple layers, add R-values of each layer to determine overall R-value.

3. If the overall R-value of the floor protector system is equal to or greater than the floor protector

specifications given, the alternate is acceptable.

Definitions:

Thermal conductance(C) =

BTU

=

W

(hr)(ft

2

)(°F)

(m

2

)(°K)

Thermal conductivity (k) =

(Btu)(inch)

=

W

=

Btu

(hr)(ft

2

)(°F)

(m)(°K)

(hr)(ft)(°F)

Thermal resistance (R) =

(ft

2

)(hr)(°F)

=

(m

2

)(°K)

Btu

W

Example:
The specs of floor protector material should be 3/4-inch thick material with a k-factor of 0.84.
The proposed alternative material is 4” brick with a C-factor of 1.25 over 1/8-inch mineral board
with a k-factor of 0.29.
Step 1: Convert specs to R-value.

R = 1/k x T = 1/0.84 x 0.75 = 0.893 System must have a R-value of 0.893 = Rspecs

Step 2: Calculate R-value of individual components

4” Brick with C-factor = 1.25. R = 1/C = 1/1.25 = 0.80 = Rbrick

1/8-inch (0.125”) mineral board with k-factor = 0.29. R = 1/0.29 x 0.125 = 0.431 = Rmin.brd.

Step 3: Add R-values of components to get total R-value of system

Rbrick + Rmin.brd = 0.80 + 0.431 = 1.231 = Rsystem

Step 4: Compare Rsystem to Rspecs

Rsystem = 1.231 is larger than Rspecs of 0.893. System R-value exceeds the required

specifications and therefore is an acceptable alternative.