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2 gain calculation recommendations, Calculate the compensation capacitor value, Verify the op amp compensation – Cirrus Logic CS3002 User Manual

Page 11: Cs3002

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CS3002

DS490F10

11

3.2.2 Gain Calculation Recommendations

Condition 1: |Av|

50 and R1 100

The op amp is inherently stable for |Av|

 50 and

R1

 100. Capacitor C2 is not required for

compensation across resistor R2.

1) |Av| = 1 configuration has 70° phase margin and

20dB gain margin.

2) |Av| = 50 configuration has phase margin between

40° for C

LOAD

 100 pF and 60° for C

LOAD

 0pF.

Condition 2: |Av|

50 and R1 100

Compensation capacitor C2 across resistor R2 is
required. Calculate C2 using Equation 8:

where

C

in

= 50pF

Condition 3: |Av|

50

Compensation capacitor C2 across resistor R2 is
required. Calculate and verify a value for C2 using the
following steps.

Calculate the Compensation Capacitor Value:

1) Calculate a value for C2 using Equation 9:

where

P

1

= 1MHz

To simplify the calculation, set the pole of the filter to
P

1

= 1MHz. Pole P

1

must be set higher than the

op amp’s internal 50kHz crossover frequency.

2) Calculate a second value for C2 using Equation 10:

where

C

in

= 50pF

3) Use the larger of the two values calculated in steps

1 and 2.

Verify the Op Amp Compensation:

Verify the op amp compensation using the open-loop
gain and phase response Bode plot in

Figure 13.

Plot

the calculated closed loop gain transfer function and
verify the following design criteria are met:

1) Pole P

1

> op amp internal 50kHz crossover

frequency

where

P

1

= 1MHz

To simplify the calculation, set the pole to P

1

= 1MHz.

2) Z1 < op amp internal 50kHz crossover frequency

3) Gain margin above the open-loop gain transfer

function is required. A gain margin of +20dB above
the open-loop gain transfer function is optimal.

C2

R1 C

in

R2

---------------------------

[Eq. 8]

C2

1

2

 R1 R2



 P

1

---------------------------------------------------

=

[Eq. 9]

C2

R1 C

in

R2

---------------------------

[Eq. 10]

P

1

1

2

 R1 R2



 C2

-----------------------------------------------

=

[Eq. 11]

Z

1

1

2

 R2 C2

----------------------------------

=

[Eq. 12]