Field correction of calibration factor – Liquid Controls AN25 User Manual
Page 8

Sponsler Co., Inc.
AN25 Totalizer/Rate Indicator
pg. 8
DOC#: MN-AN25
Example #5:
The Engineering Unit is pounds in 10
th
s CO
2
K-Factor = 250 pulses per gallon
Pounds of CO
2
= 8.470 per gallon
In order to establish 10
th
s, increase lbs./gal. by a factor of 10
C.F. = 84.7/250
C.F. = .3388
On the Factoring P.C.B.:
Set S6 #1 ‘ON’ (
↓ Position) ÷ 1 does not move decimal point
Set S2@3, S3@3, S4@8, S5@8
Set S1 in ‘0’ Position
If the gallons per unit volume such as 7.48 gallons per FT
3
is known, but not the unit volume per gallon as
required to calculate the calibration factor; take the reciprocal of gallons per unit volume to derive the unit
volume per gallon.
7.48 gallons per FT
3
1/7.48 = .13369 FT
3
per gallon
Example #6:
The engineering unit is ACF (FT
3
)
K-Factor = 250 pulses per gallon
ACF = .13369 per gallon
C.F. = .13369 / 250
C.F. - .0005348
On the Factoring P.C.B.:
Set S6 #4 ‘ON’ (
↓ Position) Moves decimal point right 3 places
Set S2@5, S3@3, S4@4, S5@8
Set S1 in ‘0’ Position
Example #7:
Desired Engineering Unit is ACF x 10
K-Factor = 250 pulses per gallon
ACF = .13369 per gallon
In order to establish x 10, decrease ACF/gal by a factor of 10
C.F. = .013369 / 250 = .00005348
On the factoring P.C.B.:
Set S6 #5 ‘ON’ (
↓ Position) Moves decimal point right 4 places
Set S2@5, S3@3, S4@4, S5@8 (.5348)
Set S1 in ‘0’ Position (0.5348)
Field Correction of Calibration Factor
To adjust the calibration factor to reflect the turbine’s actual response to the operating conditions, incorporate the
following formula:
New C.F =
Actual Quantity
x Present C.F.
Displayed Quantity