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7 ac power draw and thermal dissipation – Crown Audio STUDIO AMPLIFIER User Manual

Page 36

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Page 36

Studio Reference

IIIII & II

II

II

II

II

Professional Studio Amplifiers

7 AC Power Draw and

Thermal Dissipation

This section provides detailed information about the
amount of power and current drawn from the AC mains
by

Studio Reference amplifiers and the amount of heat

produced under various conditions. The calculations
presented here are intended to provide a very realistic
and reliable depiction of the amplifiers. The following
assumptions were made:

• The amplifier’s available channels are loaded, and

full, standard 1 kHz power is being delivered.

• Amplifier efficiency at standard 1 kHz power is

estimated to be 65%.

• Quiescent power draw is 90 watts (an almost

negligible amount for full-power calculations).

• Quiescent thermal dissipation equals 307 btu/hr at

90 watts.

• Duty cycle takes into account the typical crest factor

for a particular type of source material.

• Duty cycle of pink noise is 50%.

• Duty cycle of highly compressed rock ‘n’ roll

midrange is 40%.

• Duty cycle of uncompressed rock ‘n’ roll is 30%.

• Duty cycle of background music is 20%.

• Duty cycle of continuous speech is 10%.

• Duty cycle of infrequent paging is 1%.

Here are the equations used to calculate the data pre-
sented in Figures 7.1 and 7.2:

The estimated quiescent power draw of 90 watts is a
maximum figure, and assumes the fan is running at
high speed. The following equation converts power
draw in watts to current draw in amperes:

Current Draw

(amperes)

=

AC Mains Power

Draw (watts)

x

AC Mains

Voltage

Power

Factor (.83)

The power factor constant of 0.83 is needed to
compensate for the difference in phase between in the
AC mains voltage and current. The following equation
was used to calculate thermal dissipation:

Total output power with all

channels driven (watts)

Thermal

Dissipation

(btu/hr)

=

+

Quiescent Power

Draw (90 watts)

x Duty

Cycle

Amplifier Efficiency (.65)

(

)

x 3.415

.35

x

The constant 0.35 is inefficiency (1.00 – 0.65) and the
factor 3.415 converts watts to btu/hr. Thermal dissipa-
tion in btu is divided by the constant 3.968 to get kcal. If
you plan to measure output power under real-world
conditions, the following equation may be helpful:

Total output power with all

channels driven (watts)

Thermal

Dissipation

(btu/hr)

=

+

Quiescent Power

Draw (90 watts)

x Duty

Cycle

Amplifier Efficiency (.65)

(

)

x 3.415

.35

x

8 Ohm Stereo / 16 Ohm Bridge-Mono / 4 Ohm Parallel-Mono

L O A D

50%

40%

30%

20%

10%

1325

1075

830

585

340

1,780

1,485

1,190

900

605

1,925

1,555

1,190

825

460

630

520

410

300

190

15.9

12.9

10.0

7.0

4.1

23.1

18.7

14.3

9.9

5.5

Duty

Cycle

AC Mains

Power

Draw

(Watts)

btu/hr

Current Draw (Amps)

7.2

5.9

4.5

3.2

1.8

10.5

8.5

6.5

4.5

2.5

4 Ohm Stereo / 8 Ohm Bridge-Mono / 2 Ohm Parallel-Mono

Studio Reference I

450

375

300

230

155

kcal/hr

2,500

2,060

1,620

1,185

745

100-120 V 220-240 V

Thermal Dissipation

btu/hr

Current Draw (Amps)

kcal/hr

100-120 V 220-240 V

Thermal Dissipation

AC Mains

Power

Draw

(Watts)

Fig. 7.1 Studio Reference

I Power Draw, Current Draw and

Thermal Dissipation at Various Duty Cycles

This manual is related to the following products: