Napoleon Fireplaces GE38NT-M - Manual (Page 10)

10
W415-0429 / C / 11.04.05
Example 4:
V
1
=5 ft
V
2
=10 ft
V
T
= V
1
+ V
2
= 5 + 10 = 15 ft
H
1
=1 ft
H
2
=3 ft
H
3
=2.5 ft
H
R
= H
1
+ H
2
+ H
3
= 1 + 3 + 2.5 = 6.5 ft
H
O
= .03(four 90° elbows - 90°)
= .03(90 + 90 + 90 + 90 - 90) = 8.1 ft
H
T
=H
R
+ H
O
= 6.5 + 8.1 = 14.6 ft
H
T
+ V
T
= 14.6 + 15 = 29.6 ft
Formula 1: H
T
< V
T
14.6 < 15
Formula 2: H
T
+ V
T
< 40 feet
29.6 < 40
Since both formulas are met, this vent configuration is ac-
ceptable.
when (H
t
) < (V
t
)
Simple venting configurations
FIGURE 10
FIGURE 11
For vent configurations requiring elbows, the following for-
mulas apply:
Formula 1: H
T
< V
T
Formula 2: H
T
+ V
T
< 40 feet
See graph to determine the required vertical rise V
T
for the
required horizontal run H
T
.
90°
90°
90°
V
2
90°
H
1
V
1
H
3
H
2
REQUIRED
VERTICAL RISE
IN FEET
V
T
HORIZONTAL VENT RUN PLUS OFFSET IN FEET H
T
The shaded area within the lines represents acceptable
values for H
T
and V
T
.
TOP EXIT VERTICAL TERMINATION