Lab.gruppen fP 6400 - Manual (Page 13)

an average output power equal to 1/8 of full power. The one eighth of the total power is as loud as you
can play music while making some attempt to avoid obvious clipping. It also corresponds to a headroom
of 9dB, which is very low for regular audio program.
able 3
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e calculated as in the following example:
4 ohms load on an amplifier
tts, and
to the chart above is then 1975 watts. This chart shows the active
he heat power produced is the difference between the power consumption and output power:
roduced in watts, in kcal per hour, and also in BTU per hour.
he efficiency can also be calculated, it being the output-power divided by the input-power:
Power* AFS activated 1/3 Power 1/8 Power Idle
[W] [W] ** ***
fP 6400 8 ohms 2x 1300 1300 1230 575 105
4 ohms 2x 2300 1450 1975 900 105
2 ohms 2x 3200 1850 2950 1290 105
* = Will be reduced by AFS limiter.
** = Average power with music as program source. The amplifier driven to clip level.
*** = Regular music power with 9dB headroom, IEC standard power rating.
MAINS INPUT POWER MAX OUTPUT POWER
T
The heat power can b
We consider a headroom of at least 5dB (1/3 of full power) and a
producing 2300 watts per channel. The 1/3 power per channel is accordingly 2300 / 3 = 767 wa
total output 2 x 767 = 1534 watts.
The power consumption according
power consumption of the amplifier with different loads and power levels.
T
1975 - 1534 = 441 watts per amplifier.
The chart below shows the heat power p
1/3 Power* 1/8 Power** 1/3 Power* 1/8 Power** 1/3 Power* 1/8 Power**
[W] [W] kcal / h kcal / h BTU / h BTU / h
fP 6400 8 ohms 363 250 310 220 1240 850
4 ohms 442 325 380 280 1510 1110
2 ohms 817 490 700 420 2790 1670
* = Average power with music as program source. The amplifier driven to clip level.
** = Regular music power with 9dB headroom, IEC standard power rating.
HEAT POWER
T
1533 watts / 1975 watts= 78%.
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