FORD 2015 Fiesta - Manual (Page 153)

- 150 = 150 pounds. Yes, you have
enough load capacity in your
vehicle to transport four friends
and your golf bags. In metric units,
the calculation would be: 635
kilograms - (5 x 99 kilograms) -
(5 x 13.5 kilograms) = 635 - 495 -
67.5 = 72.5 kilograms.
*Suppose your vehicle has a
1400-pound (635-kilogram) cargo
and luggage capacity. You and
one of your friends decide to pick
up cement from the local home
improvement store to finish that
patio you have been planning for
the past two years. Measuring the
inside of the vehicle with the rear
seat folded down, you have room
for twelve 100-pound
(45-kilogram) bags of cement. Do
you have enough load capacity to
transport the cement to your
home? If you and your friend each
weigh 220 pounds (99 kilograms),
the calculation would be: 1400 -
(2 x 220) - (12 x 100) = 1400 - 440
- 1200 = - 240 pounds. No, you do
not have enough cargo capacity
to carry that much weight. In
metric units, the calculation would
be: 635 kilograms - (2 x 99
kilograms) - (12 x 45 kilograms) =
635 - 198 - 540 = -103 kilograms.
You will need to reduce the load
weight by at least 240 pounds
(104 kilograms). If you remove
three 100-pound (45-kilogram)
cement bags, then the load
calculation would be: 1400 - (2 x
220) - (9 x 100) = 1400 - 440 -
900 = 60 pounds. Now you have
the load capacity to transport the
cement and your friend home. In
metric units, the calculation would
be: 635 kilograms - (2 x 99
kilograms) - (9 x 45 kilograms) =
635 - 198 - 405 = 32 kilograms.
The above calculations also
assume that the loads are
positioned in your vehicle in a
manner that does not overload
the Front or the Rear Gross Axle
Weight Rating specified for your
vehicle on the Safety Compliance
Certification Label. The label shall
be affixed to either the door hinge
pillar, door-latch post, or the door
edge that meets the door-latch
post, next to the driver's seating
position.
150
Fiesta (CCT), enUSA, Second Printing
Load Carrying