Calculated Industries 4215 - Manual (Page 38)

Concrete Columns
You’re going to pour five columns,
each with a diameter of 3 feet 4-1/2
inches and a height of 11 feet 6 inches.
How many cubic yards of concrete are
needed for all five columns? If the con-
crete weighs 1.75 tons per cubic yard,
what is the total weight in tons? In
pounds? In kilograms?
Step/Keystrokes Display
1. Clear calculator:
[On/C] [On/C] 0.
Find Cross-sectional Area of Column
2. Enter diameter and find surface area:
3 [Feet] 4 [Inch] 3 FT 4- 1.2 IN
1 [/] 2 [Circ] [Circ] 8.946176 SQ FT
Find Volume
3. Multiply by height and convert to
cubic yards:
[x] 11 [Feet]
6 [Inch] [=]
102.881 CU FT
[Conv] [Yds] 3.810408 CU YD
4. Multiply by 5 columns and enter into
Memory:
[x] 5 [=]
19.05204 CU YD
[M+]
38 – ConcreteCalc™