Field Controls Solution For Great Indoors 24v - Manual (Page 10)

10
UV-AIRE ®
Air Purification System
UV dose required for the de-activation of various microbes
Bacteria UV Dose Mold UV Dose
Serratia Marcescens 6,160 Aspergillus amstelodami 77,000
Legionnella bozemanii 3,500 Mucor Mucedo 77,000
Legionnella micdadei 3,100 Penicillium chrysogenum 56,000
Mycobacterium tuberculosis 10,000 Yeast UV Dose
Salmonella enteritidis 7,600 Baker's Yeast 8,000
Salmonella typhi (Typhoid Fever) 7,000 Brewer's Yeast 13,200
Streptococcus hemolyticus 5,500
Virus UV Dose
Adeno Virus Type III 4,500
Infectious Hepatitis 8,000
Influenza 6,600
Rotavirus 24,000
UV dose is measured in microwatt
seconds per centimeter squared
(µW-sec/cm2). The information
presented is intended to give the reader
a general idea of how UV disinfects,
based upon various credible resources.
We do not guarantee its accuracy in
any way.
The Bird Flu Virus is a type of Influenza. Since the kill rate
for the influenza virus is 6,600 microwatts of UV energy, it is
reasonable to conclude that the Bird Flu virus can be
reduced or eliminated by 6,600-10,000 microwatts.
Bird Flu Virus (Avian Flu)
Most, if not all bacteria can be destroyed by the
use of UV light. The main factors in disinfection are
the amount of UV power the lamp produces and
the length of time the bacteria is exposed to the UV
light source.
The energy required to kill microorganisms is a
product of the UV light’s intensity and exposure
time. This energy is measured in microwatt seconds
per square centimeter.
Intensity x Exposure Time = microWatt seconds/cm 2
Table 1 lists the amount of UV energy (measured in
µW-sec/cm
2 ) necessary to destroy various bacteria.
Independent lab testing of the UV-Aire shows that
in a single-pass air flow test, one 18-inch UV-Aire
lamp can reduce levels of Serratia Marcescens (a
typical bacteria) by 93%, while a two lamp system
can reduce by 99%.
1
The calculated average UV energy output levels of
a single UV-Aire lamp in an 18-inch square duct is
2,608 µW-sec/cm2 and 6,186 µW-sec/cm
2 for a
two lamp system. The 6,186 is comparable to the
99% energy required for Serratia Marcescens. It
can be seen that there is a direct correlation
between the UV-Aire UV lamp output and the
observed kill rates in the lab.
Correlating The Lab Test With Other Bacteria
Use the chart below to estimate the effectiveness of
the UV-Aire with other bacteria.
Harder–to–kill bacteria and molds require greater
energy or exposure time to be as effective. For
example, 99% reduction of Rotavirus requires
24,000 µW-sec/cm
2 of UV energy versus 6,600
µW-sec/cm 2 for Influenza virus (see table below).
This means that Rotavirus spores are five times
more resistant than Influenza. Consequently, spores
will require five times the UV output energy from
the lamp or five times greater exposure time. For
practical purposes, we recommend trapping the
spores in a high efficiency filter downstream of the
UV-Aire which can be irradiated continuously with
the UV-Aire lamp.
For details of the lab test ask for form number 4291.
1. Efficiency of Bacterial Disinfection by a Duct-mounted UV-Aire ® Air Purifier: by
Microbe Management
UV Energy Required To Kill Bacteria
Distance
from Lamp
Intensity
Factor
0 354
1" 127
2" 69
4" 32
6" 20
8" 14
10" 14
Distance
from Lamp
Intensity
Factor
15" 6
20" 4
25" 3
30" 2
35" 1.4
39.97" 1
UV lamp intensity is rated at a distance of
one meter. To determine the intensity of
ultraviolet radiation at different distances
from the lamp, multiply the intensity of the
lamp by the intensity factor shown in the
models and specifications chart.
Example: To determine the ultraviolet
intensity of the UV-18 at a distance of six
inches, multiply 73 by 20 to yield 1460
µW-sec/cm
2 .
Lamp Intensity